(06-13-2015, 04:30 PM)Error Wrote:

(06-13-2015, 04:24 PM)nOmnomnOm Wrote: You got me confused.... but let me clarify a little what I am trying to do here.

I am making a model of a base i wana design that has parts of it that turn. The parts that turn are circular in shape where the people would live inside the outer circle. This is done in space and im reducing friction to minimal using magnets and all that jazz.

So to make an artificial gravity i need 9.81 for horse.

The velocity is what I am trying to imagine.... how fast is too fast for a person???

The mass will be decided once i figure out the radius.... but i think i have 2 unknowns so far....

But here is the issue though... do i have to use the mass of the WHOLE wheel or can I use mass per meter squared? That would be way more simple to do for me to figure things out.

Ah, right, got it; that's a bit more complicated, but you could indeed just check on a point of the wheel to find the acceleration there, as you suggested below. You don't even need to multiply by a mass in the first place if you just want to find the acceleration at some radius and rotational speed; a = (v^2)/r.

(06-13-2015, 04:33 PM)Error Wrote: Yup, pretty much!

(06-13-2015, 05:18 PM)Error Wrote: The force will of course vary between different objects, but that's a non-issue; it already does that here on Earth and in other gravity wells, as the gravitational acceleration is more or less constant at sea level, but people (and other objects that rest on the ground) have different masses and thus exert different forces upon the ground. Getting the acceleration close to 9.81 m/s^2 at the ring's "floor" is what's critical, not the force each individual is applying to it, as that is only a function of their mass (which is constant) and the acceleration (which we can determine by changing the ring's radius or rotational speed) given by the good old F = ma.

Another thing to note: If the radius of the ring is very small compared to the height of the objects you want to experience about 1 g (i.e. the people aboard your space station), keep in mind that they will experience different acceleration over the length of their bodies, since anything closer to the centre (heads and such) will experience a different centripetal acceleration a given by a=(v^2)/r; you can get away from that issue by making the radius of the ring large in comparison to the people on it, so that the difference in acceleration between their heads and feet will be insignificant. Shouldn't matter all that much, though.

(06-13-2015, 05:38 PM)Error Wrote: The middle of an average person should work quite well. The velocity wouldn't matter as long as it is constant; humans can't "feel" velocity in any way unless they have an external reference point (such as the trees beside a road when you're moving in a car, or the stars in space) that can tell you that you are moving. The 1 g I mentioned is just the Earth's gravitational acceleration of 9.81 m/s^2 again; the constant g is equal to 9.81. m/s^2.

(06-13-2015, 06:00 PM)Max Morse Wrote: Are you planning on a Von Braun type rotating station? Or is it going to be more spherical?